from the top of Tower a particle is thrown vertically downwards with a velocity of 10 metre per second. the ratio of distances covered by it in the 3rd and 2nd second of the motion is ( take g as 10)
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Answer:
5:3
Explanation:
distance covered in a second is- u+a(2n-1)/2
put values of time in the 'n' variable and divide to find the ratio
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