Physics, asked by harshini80, 11 months ago

from the top of Tower a particle is thrown vertically downwards with a velocity of 10 metre per second. the ratio of distances covered by it in the 3rd and 2nd second of the motion is ( take g as 10)​

Answers

Answered by sidmusk
2

Answer:

5:3

Explanation:

distance covered in a second is- u+a(2n-1)/2

put values of time in the 'n' variable and divide to find the ratio

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