Question

From the velocity time graph shown below find the acceleration of body b/w A and b.
brainly main koi ginieus nahin hai kya .give answer in detail other wise I am report then​

Answer 1

a) from the figure, it is clear that velocity is 40m/s

b) a = v-u / t

= 40-20 / 3

= 20/3 m/s sq= 6.67 m/s sq

c) between b and c,the velocity is constant. acceleration is change in velocity per unit time.

sine there is no change in velocity, acceleration will be 0

d) when the obj reaches d, velocity is zero. therefore final velocity is zero.

v-u / t

= -40 / 2 s

= -20 m/s sq

e) displacement = area under graph

= calculate area of rectangle and triangle

area of rectangle= 40 m/s * 3 s = 120 m

Area of triangle = 1/2 * l * h = 1/2 * 40 * 2

= 40 m

sum = 120+40 = 160 m