Question

from top of a tower 200m in heighr a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 50m/s find when and where the two balls will meet​

Answer 1

Explanation:

The distance travelled by the body dropped from the height is given as

s=ut+

2

1

gt

2

s=50t−5t

2

Both the body will together travel the distance of 200m

Hence

200=(50t−5t

2

)+5t

2

Time taken is4sec

Distance travelled by the falling stone is

s=

2

1

gt

2

s=5×8=80m

The distance travelled by the projected body is

s=50×4−5×4

2

s=120m

So both body will meet at 120m above the ground.

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