Math, asked by shubhammunda607, 4 days ago

ftom rs aggarwl of standerd 9​

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Answered by XxitzZBrainlyStarxX
34

Question:-

\sf( \sqrt{ \frac{3}{5} } ) {}^{x - 1}  = ( \frac{27}{125} ) {}^{ - 1}

Solution:-

\sf( \sqrt{ \frac{3}{5} } ) {}^{x - 1}  = ( \frac{27}{125} ) {}^{ - 1}

\longmapsto \sf \: ( \frac{3}{5} ) {}^{ \frac{x - 1}{2} }  = ( \frac{3 {}^{3} }{5 {}^{3} } ) {}^{ - 1}

\longmapsto \sf \: ( \frac{3}{5} ) {}^{ \frac{x - 1}{2} }  = ( \frac{3}{5} ) {}^{ - 3}

 \therefore \sf \:  \frac{x - 1}{2}  =  - 3

\longmapsto \sf \: x - 1 =  - 6

 \longmapsto \sf \: x =  - 6 + 1 =  - 5

 \longmapsto \sf \: x  =  - 5

Answer:-

  •  \red\longmapsto \sf  \huge\underline  \mathfrak \red{x =  - 5}

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