Question

full explain plz help................​

Answer 1

a) <BAD = 45°

b) BD= 8 cm

c) <ACD = 30°

d) CD = 16 cm

e) area of ∆ ABC = 128 cm2

Explanation =

a) Sum of all angles of triangle is 180°

So that, <BDA + <ABD + <BAD = 180°

45° + 90° + <BAD = 180°

135 + <BAD = 180°

<BAD = 180 - 135

<BAD = 45°

b) < DBA = < BAD

Therefore, AD = BD ( Side opposite to the equal angles)

c) Sum of all angles of triangle is 180°

So that, < DAC + < ADC + <ACD = 180°

60° + 90° + <ACD = 180°

150° + <ACD = 180°

<ACD = 180° - 150°

<ACD = 30°

d) 1/2<DAC = <ACD

So, <DAC = 2<ACD

Then, DC = 2 AD

DC = 2 × 8

DC = 16 cm

e) ar of the ∆ = 1/2 × base × height

= 1/2 × BC × AD

= 1/2 × (8 + 16) × 8

= 1/2 × 32 × 8

= 128cm2

Hence prove

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