Fund the sum of all two digit natural no which when divided by 3 yields 1 as remainder
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Step-by-step explanation:
10,13............97
L=a+(n-1)d
97=10+(n-1)3
87=3n-3
90=3n
n=30
Now sum
Sn=n/2(a+l)
S30=30/2(10+97)
S30=15*107
1605 is the answer
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