Given triangle abc similar to triangle por if ab/pq=1/3 then find triangle abc / triangle pqr
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ΔABC~ΔPQR
AB/PQ=1/3 .......Given
A(ΔABC)/A(ΔPQR) ....(by theorem of area of similar triangle)
=AB^2/PQ^2
=1^2/3^2
=1/9
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