Question

g=GM/rsquare then value of g is at goa beach or on top of mount everest

Answer 1

It will remain same because it doesnot depend on place

Answer 2

"$g\quad =\quad \frac { GM }{ { r }^{ 2 } }$

Where,

g is the acceleration due to gravity

G is the "gravitational constant" $=\quad 6.67\quad \times \quad { 10 }^{ -11 }\quad { { Nm }^{ 2 } }/{ { kg }^{ 2 } }$

M is the mass of the earth $=\quad 6\quad \times \quad { 10 }^{ 24 }\quad kg$

R is the radius of the earth $=\quad 6.4\quad \times \quad { 10 }^{ 6 }\quad m$

Substituting, we have

$g\quad =\quad 9.8\quad \frac { m }{ { sec }^{ 2 } }$

This equation holds true for objects on or near the earth's surface. This is because the earth's sphere is not perfect shape and 'g' value increases towards the "poles than at the equator".

For such a situation, the equation for 'g' becomes,

$g\quad =\quad \frac { GM }{ { d }^{ 2 } }$

Where,

d is the "distance" from the object to the earth.

So, the above equation refers to 'g' at earth's surface at Goa beach."