Question

G.
If each toy
Paul bought two toy cars at the toy store
can cost RS ses and he pays
Rs 20 how much change should he t
back​

Answer 1

Let the no of toys be x and price of each toy be y

therefore, xy = 360

and x=360/y {eg -1}

2nd condition

(x+2)(y-2)=360

xy + 2y - 2x - 4 = 360

2y - 2(360/y) - 4 = 0 { since xy=360 & from eq 1}

 - 4y -720 = 0

 - 2y - 360 =0

 - 20y +18y -360 =0

y(y-20) +18(y-20) = 0

(y+18)(y-20)=0

therefore y= -18 or y = 20

in this case y=20 since price of quantity cannot e in negative

therefore the original price of toy is 20 rupees