g product using appropriate identities
5) (ii) (p - 3) (p + 3) (iii) (-1) (-1)
4) (v) 102 x 98
al in factorisation of algebraic expressions. Let us see some
e
(ii) 9x2 - 25
(iv) 49x² - 112xy + 64y
6 + 16b
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Answer:
here is your answer
Step-by-step explanation:
5) (p-3)(p+3)
here we have to use this identity
(a-b) (a+b) = a^2-b^2
a=p,and b=3
according to identity
p^2-3^2
p^2-9
(-1)(-1)
1
4) 102×98
(+2)(100-2). same identity as we used in 5 part
100^2-2^2
10000-4
9996
49x^2-112xy+64^y
(a-b) = a2- b2- 2 ab
a=7 and b= 8
(7-8)^2
that's all I can help u
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