Math, asked by mhimasree, 7 months ago

g product using appropriate identities
5) (ii) (p - 3) (p + 3) (iii) (-1) (-1)
4) (v) 102 x 98
al in factorisation of algebraic expressions. Let us see some
e
(ii) 9x2 - 25
(iv) 49x² - 112xy + 64y
6 + 16b​

Answers

Answered by rosejasica
0

Answer:

here is your answer

Step-by-step explanation:

5) (p-3)(p+3)

here we have to use this identity

(a-b) (a+b) = a^2-b^2

a=p,and b=3

according to identity

p^2-3^2

p^2-9

(-1)(-1)

1

4) 102×98

(+2)(100-2). same identity as we used in 5 part

100^2-2^2

10000-4

9996

49x^2-112xy+64^y

(a-b) = a2- b2- 2 ab

a=7 and b= 8

(7-8)^2

that's all I can help u

may it will heil you

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