Question

g(t)= -(t-1)^2 +5g(t)=−(t−1)
2
+5g, left parenthesis, t, right parenthesis, equals, minus, left parenthesis, t, minus, 1, right parenthesis, squared, plus, 5
Over which interval does ggg have an average rate of change of zero?

Answer 1

Answer:

0 ≤ t ≤ 2

Step-by-step explanation:

Here the given function is

g(t) = - (t - 1)² + 5

Now

g(0) = - (0 - 1)² + 5 = -1 + 5 = 4

Again

g(2) = - (2 - 1)² + 5 = -1 +5 = 4

Average rate of change of g(t) over the interval – 0 ≤ t ≤ 2

g(2) - g(0)

= _________

2 - 0

= (4 - 4 )/ 2 = 0

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