Question

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$x - 3 \div {x}^{3} - {3x}^{2} + 4x - 12$
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Answer 1

Step-by-step explanation:

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navya2644

25.12.2018

Math

Secondary School

+20 pts

Answered

Find all the zeroes of the polynomial x3+3x2-4x-12 if one of its zeroes is -3

2

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Answers

gaurav2013c

gaurav2013c Genius

Solution is in the attached image..

5.0

2 votes

THANKS

2

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rajeev378

rajeev378 Genius

\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate}}}

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Here is your answer

{x}^{3} + 3 {x}^{2} - 4x - 12 = 0 \\ {x}^{2} (x + 3) - 4(x + 3) = 0 \\ (x + 3)( {x}^{2} - 4) = 0 \\ x + 3 = 0 \\ x = - 3 \\ or \\ {x}^{2} - 4 = 0 \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = 2 \: \: and \: - 2

Therefore the roots of the equation are

-3 , 2. and -2

Answer 2

Answer:

I don't know now what to do but