Question

g(x)=x^2-4 what is the value of g(x)-g(-x)
find the value
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Answer 1

Answer:g(-4) = 8

Step-by-step explanation:

g(4)=8

8=a*(4)^2 + 24

8=a*16 + 24

8–24=a*16

-16=a*16

a= -1

g(x) = (-1)x^2 + 24

g(-4) = (-1) * (-4) ^2 + 24

g(-4) = -16 + 24

g(-4) = 8

Answer 2

g(x) = x² - 4

→ 0 = x² - 4

→ 4 = x²

→ x = √4

= 2

Hence, 2 is the zero of the polynomial g(x)

Now,

g(x) - g(-x)

x²- 4 - {-(x² - 4)}

= 2² - 4 - { - ( 2² - 4)}

= 4-4 - {- ( 4- 4)}

= 0 + 0

= 0