g(x) = x3 + 2x2 − 5x − 6 Find the x-values for y= 3
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Step-by-step explanation:
Let g(x)=x3−2x2−5x+6
⇒g(1)=13−212−5×1+6=1−2−5+6=0
Using synthetic division, we have
x2−x−6=0 is the other factor
(x−1)(x2−x−6)=0
=(x−1)(x2−3x+2x−6)=0
=(x−1)(x(x−3)+2(x−3))=0
=(x−1)(x+2)(x−3) are the factors of f(x)
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