g(y) = y +5;
p(y) = y2-2y+a
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Is the answer okk?????
But can I ask you something...
These are the same kind of problems and I am solving these in a same manner... Do you understand it????
Step-by-step explanation:
g(y) =y+5=0
=>y=-5
Now g(y) is a factor of p(y) so the reminder is zero here,,
P(-5)=(-5)^2-2(-5)+a=0
=>25+10+a=0
=>a=-35
The value of a=-35
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