Chemistry, asked by abhinavsharma4999, 4 months ago

∆G° (kJ/mol) for a reaction at 127°C is -38.294 with equilibrium constant is 10^x then the value of x is

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Answered by vandanajha7290

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Answer:

∆G° (kJ/mol) for a reaction at 127°C is -38.294 with equilibrium constant is 10^x then the value of x is

Explanation:

∆G° (kJ/mol) for a reaction at 127°C is -38.294 with equilibrium constant is 10^x then the value of x is

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