Question

ग) दो विभिन्न पासों को एक साथ उछाला जाता है । एक
द्विक आने की प्रायिकता ज्ञात कीजिए।​

Answer 1

Given that,

Two different passes are tossed together.

We know that,

When two different passes are tossed together then,

The total number of results

n(S) = (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6),(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

$n(S)=36$

Probability of same number on different passes,

$n(A)=(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)$

$n(A)=6$

We need to calculate the probability of a biennial

Using formula of probability

$P(A)=\dfrac{n(A)}{n(S)}$

Put the value into the formula

$P(A)=\dfrac{6}{36}$

$P(A)=\dfrac{1}{6}$

Hence, The probability of a biennial is $\dfrac{1}{6}$