Question

gad
calculate the mass of the carbon dioxide and water
formed on compte combusion of 24g of methane.
catomic mags c= 12 u H=1u =, 0= 16 u
​

Answer 1

Given,

Chemical Reaction:

CH₄ (g) + 2O₂ (g) -------> CO₂ (g) + 2H₂O (l)

By Gay-Lussac's Law,

From this reaction, it is clear that 1 volume of Methane burns in 2 volumes of Oxygen producing 1 volume of Carbon Dioxide and 2 volumes of Water however, volume of water will be considered 0 because it's a liquid.

Given Mass of Methane = 24 g

Mass of Carbon Dioxide formed = 24 g

Mass of Water = Negligible

I hope this helps.