Galvanometer of resistance 50 ohm gives full scale deflection for a current of 0.25 ampere calculate the required resistance to convert the galvanometer into an ammeter of range 5 ampere.
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Explanation:
The voltage drop across the galvanometer when full rated current flows through it is equal to
V=I*Rg
=0.005*50
=0.25 Volt
The arrangement of conversion of galvanometer to ammeter is as given below.
If the galvanometer is converted to read 15 volts, resistance in series with galvanometer coil is connected. The voltage drop across the resistance should be equal to
15–0.25=14.75 volt, when the current through the series circuit is 5mA.
The value of series resistance
=14.75/0.005
=2950 Ohms
=2.95 Kilo Ohms
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