Garima and Tanu Started walking from the opposite ends of a linear track xy of 800m. If both of them meet at 560m from point x, then determine the ratio of their speed.
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Assume that Garima started from point 'x' and Tanu started from point 'y'
Also, assume that Garima walked distance of 560 meters. Then Tanu walks 240 meters as the total distance is 800 meters.
Let Garima travelled 'a' seconds to reach the distance of 560 meters.
Let Tanu travelled 'b' seconds to reach the distance of 240 meters
Distance=Speed*Time
Speed=Distance/Time
Speed of Garima=560/a
Speed of Tanu=240/b
Let the ratio of speed between Garima and Tanu be 'r'
=> r = 560/a : 240/b
=> r = 560b:240a
=> r = 7b:3a
Hope it helps
Also, assume that Garima walked distance of 560 meters. Then Tanu walks 240 meters as the total distance is 800 meters.
Let Garima travelled 'a' seconds to reach the distance of 560 meters.
Let Tanu travelled 'b' seconds to reach the distance of 240 meters
Distance=Speed*Time
Speed=Distance/Time
Speed of Garima=560/a
Speed of Tanu=240/b
Let the ratio of speed between Garima and Tanu be 'r'
=> r = 560/a : 240/b
=> r = 560b:240a
=> r = 7b:3a
Hope it helps
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