Garrison of 120 men has provision for 30 days at the end of 5 days 5 more men joined them how many days can they sustain on the remaining provision
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Answered by
29
we know that no. of days is inversely propotional to the provision for men.
So for 120 men the provision would last for 30days. (given)
Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
A.t.q 120*30 = 120*5+125*x
(120*30) - (120*5)= 125x
120(30-5)=125x
120 * 25 = 125x
120 = 5x
x=120/5
x= 24
so the provision would remain for more 24 days
So for 120 men the provision would last for 30days. (given)
Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
A.t.q 120*30 = 120*5+125*x
(120*30) - (120*5)= 125x
120(30-5)=125x
120 * 25 = 125x
120 = 5x
x=120/5
x= 24
so the provision would remain for more 24 days
Answered by
6
Answer:
Step-by-step explanation:
Hope this will help you
Step-by-step explanation:
For 120 men the provision would last for 30days.
∴ The provision for 1 men would sustain for. 120 x 30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
Now according to the question
⇒ 120 × 30 = 120 × 5 + 125 × x
⇒ 3600 – 600 = 125x
⇒ 3000 = 125x
So, the provision would remain for more 24 days.
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