Question

 garrison of 240 men has provisions for 60 days.At the end of 10 days,10 more joined them.How many days can they sustain on the remaining provisions?​

Answer 1

48 days
See the photo attached for solution

Answer 2

Case 1

men = 240

days for provision = 60

Case 2

men = 250

days for provision = 50

inverse variation

$x_{1} : x_{2} : y_{2} : y_{1}$

=> 240 : 250 :: x : 50

=> 250 x = 240 × 50

=> x = $\frac{240}{250} \frac{50}{1}$

=> x = 48

Therefore, the food will be sustained for 48 days