gas is heated oc to 100c at 1atm pressure if the initial volume of the gas is 10 l find its volume
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V ∝ T
Or, T1 /T2 = V1 /V2
Since initial temperature is not given i am taking the temperature of starting point as room temperature.
Let the initial volume be V
And initial temperature(T1) be room temperature that is 25°C or 298 K (273 K +25)
Then T2 = 127°C or (273 K +127 ) 400 K
Now V2 = V1/T1 x T2
= V ×400 K298 K
= 1.34 V
Increase in volume = 1.34 V -V = 0.34 V
% increase in volume = 0.34 V/V x 100 = 34%
Or, T1 /T2 = V1 /V2
Since initial temperature is not given i am taking the temperature of starting point as room temperature.
Let the initial volume be V
And initial temperature(T1) be room temperature that is 25°C or 298 K (273 K +25)
Then T2 = 127°C or (273 K +127 ) 400 K
Now V2 = V1/T1 x T2
= V ×400 K298 K
= 1.34 V
Increase in volume = 1.34 V -V = 0.34 V
% increase in volume = 0.34 V/V x 100 = 34%
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