Math, asked by Anonymous, 8 months ago

Gaurav travels 300 km to his home partly by train and partly by bus. He takes 4 hours if he travels 60 km by train and the remaining by bus. If he travels 100km by train and the remaining by bus, he takes 10 minutes longer. Find the speed of the train and the bus separately​

Answers

Answered by datarajvaidya
0

Answer:

Let the speed of the train be x km/hr and the speed of the bus is y km/hr.

So according to question and using Time=SpeedDistance

Total distance =300 km

Roohi travels 60 km by train and 300−60=240 by bus in 4 minute,

x60+y240=4

and 100 km by train, 300−100=200 by bus, and takes 10 minutes more,

x100+y200=4+6010⇒x100+y200=625

Now, let x1=u and y1=v

then 60u+240v=4.............eq1

        100u+200v=625..............eq2

multiply eq1 by 5 and eq2 by 6 we get

300u+1200

Answered by SATYAMapjabdulkalam7
0

Answer:

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