Question

general solution for the trignometric equation:-
sin3x + sinx - sin2x=0​

Answer 1

Answer:

=sin3x+sinx-sin2x. =0

=2sin(3x+x)/2×cos(3x-x)/2-sin2x=0

=2sin2x×cosx-sin2x. =0

=sin2x(2cosx-1). =0

• sin2x=0

sin2x=sin0

2x=0

x=0

• 2cosx-1=0

2cosx=1

cosx=1/2

cosx=cos60

x=60