Question

general solution of :
1.sin x=sin y
2.cos x=cos y
3.tan x=tan y​

Answer 1

Answer:

Correct option is

C

y=(n−m)2π+(−1)n4π+(−1)m+121sin−1(−53);m,nϵZ

D

x=(m+n)2π+(−1)n4π+(−1)m21sin−1(−53);m,nϵZ

We have

⇒5sinxcosy=1 and 4tanx=tany

⇒5sinxcosy=1 and 4sinxcosy=sinycosx

⇒sinxcosy=51 and cosxsiny=54

⇒   sinxcosy+cosxsiny=1

and   sinx<