Question

general solution of the differential equation
X dy/dX = y+x sec(y/X)​

Answer 1

Answer:

p = d x d y = p + x d x d p − p 2 1 d x d p ⇒ ( x − ( 1 / p 2 ) ) d x d p = 0 ⇒ p 2 = x 1 or d x d p = 0 If d x d p = 0 then p = constant = c putting this value in given equation, we get y = c x + 1 / …

Step-by-step explanation:

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