Question

Generate random number with distinct digits in c++

Answer 1

Answer:

#include <iostream>                        

using namespace std;                      

int main() {

   int n1,n2;

   cout<<"Enter no. of digits of number you wish to get ";

   cin>>n1;

   cout<<"Enter how many numbers you want to see ";

   cin>>n2;

   int arr[n1]={0},index=0;

   for(int j=0;j<n2;j++)

   {

   int arr[n1]={0},index=0,num=0; //array to store randomly generated digit,index contain last digit containing index of array

   while(true)

   {

       int b=rand()%10;   //generating random digits less than 10

       int check=0;      //to check if digit is already found previously

       for(int i=0;i<=n1;i++)  //looping for n1 digits

       {

           if(arr[i]==b)       //checking if digit is already found previously

           check=1;            

       }

       if(check==0)            //if it's distinct digit check is 0

       {

           num=num*10+b;       //adding the digit to newly generated number

           arr[index++]=b;     //incrementing index and storing digit in array to check next time

       }

       if(index==n1)           //now if index(no. of digits found) is equal to input n1 break the loop

       break;

   }

       cout<<num<<endl;

   }

   return 0;

}

Explanation:

Comments are placed accordingly

You can compile and run.

Try to dry run it to get the logic

Hope it helps :-)