Math, asked by Anonymous, 6 months ago

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determine the fourth derivative of given function ​

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Answers

Answered by hipsterizedoll410
0

Answer: 2520t³-144

Given:

h(t)=3t^{7}-6t^{4}+8t^{2}  -12t+18

Formula used:

x^{n}=nx^{n-1}

Explanation:

First derivative,

h'(t)=7*3t^{6}-6*4t^{3}+2*8t^{1} -12\\  h'(t)=21t^{6}-24t^{3}+16t -12

Second derivative,

h''(t)=21*6t^{5}-24*3t^{2}+16\\h''(t)=126t^{5}-72t^{2}+16\\

Third derivative,

h'''(t)=126*5t^{4}-72*2t^{1}\\h'''(t)=630t^{4}-144t^{}\\\\

Fourth derivative,

h^{4} (t)=630*4t^{3}-144t^{1}\\ h^{4} (t)=2520t^{3}-144

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