Question

Genius needed here...
Solve any one

Answer 1

Answer:

Step-by-step explanation:

Let the height of the two trees AB and CD be b and a respectively.

Distance between the trees BC = p

Let EF = h be the height of point of intersection of the lines joining the top of each tree to the foot of the opposite trees.

Let CF = x then BF = (p – x)

In Δ’s ABC� and EFC,

∠ABC = ∠EFC = 90°

∠C = ∠C (common angle)

∴ ΔABC ~ ΔEFC (By AA similarity theorem)

Similarly, ΔDCB ~ ΔEFB (By AA similarity theorem)

Answer 2

here ur ans....
I m not a genius
I m only a student.......