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3-√5/2√5+3=a√5-b
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Answer:
Hey Mate Here Is Your Answer
⇒ Hi ,
LHS = ( 3 - √5 )/(3 + 2√5 )
LHS = ( 3 - √5 )/(3 + 2√5 )= [(3-√5)(2√5-3)]/[(2√5+3)(2√5-3)]
LHS = ( 3 - √5 )/(3 + 2√5 )= [(3-√5)(2√5-3)]/[(2√5+3)(2√5-3)]= [6√5 - 9 -10 + 3√5 ]/[ ( 2√5 )² - 3² ]
LHS = ( 3 - √5 )/(3 + 2√5 )= [(3-√5)(2√5-3)]/[(2√5+3)(2√5-3)]= [6√5 - 9 -10 + 3√5 ]/[ ( 2√5 )² - 3² ]= ( 9√5 - 19 )/( 20 - 9 )
LHS = ( 3 - √5 )/(3 + 2√5 )= [(3-√5)(2√5-3)]/[(2√5+3)(2√5-3)]= [6√5 - 9 -10 + 3√5 ]/[ ( 2√5 )² - 3² ]= ( 9√5 - 19 )/( 20 - 9 )= ( 9√5 - 19 )/11
LHS = ( 3 - √5 )/(3 + 2√5 )= [(3-√5)(2√5-3)]/[(2√5+3)(2√5-3)]= [6√5 - 9 -10 + 3√5 ]/[ ( 2√5 )² - 3² ]= ( 9√5 - 19 )/( 20 - 9 )= ( 9√5 - 19 )/11= ( 9/11 )√5 - 19/11 ---( 1 )
= a√5 - b ----------( 2 ) [ RHS ]
from ( 1 ) and ( 2 ) ,
a = 9/11 ,
a = 9/11 ,b = 19/11
I hope this helps you.
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