geometry of BF4- molecule on the basis of hybridisation
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Explanation:
So, the molecule will have irregular geometry and the shape is predicted by leaving the hybrid orbitals containing the lone pairs. Given a molecule is BF−4, the central atom is boron, and it has a monovalent atom, fluorine. ... So, sp3 hybridization has a tetrahedral shape.
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Answer:
Tetrahedral
Explanation:
BF4
no of electrons in valence shell=3
from F=4
negative charge=1
3+4+1=8
8/2=4 electron pairs
we have 4 bonded florines. so bond pairs=4
lone pairs=0
4=sp3
geometry=tetrahedral
shape=tetrahedral
key concept = hybridisation
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