Question

George can do some work in 8 hours. Paul can do the same work in 10 hours while hari can do the same work in 12 hours. All the three of them start working at 9 am while george stops work at 11 am and the remaining two complete the work. Approximately at what time will the work be finished? A

Answer 1

Answer:

Work finish at 1:06 PM.

Step-by-step explanation:

Given:

Number of hours taken by George = 8 hr.

Number of hours taken by Paul = 10 hr.

Number of hours taken by Hari = 12 hr.

Work start at 9 AM.

Till 11 Am All three worked.

To find: Time when the work is completed.

Work done by George in a hour = 1/8

Work done by Paul in a hour = 1/10

Work done by Hari in a hour = 1/12

Work done by all three in a hour = 1/8 + 1/10 + 1/12 = (15+12+10)/120 = 37/120

Work done by Paul and Hari in a hour = 1/10 + 1/12 = (6+5)/60 = 11/60

Work Finished by all three in 2 hr = 2 × 37/120 = 37/60

Work left to don by Hari and Paul = 1 - 37/60 = (60-37)/60 = 23/60

Time taken by Paul and Hari to finish 23/60 work = $\frac{\frac{23}{60}}{\frac{11}{60}}=\frac{23}{11}=2\frac{1}{11}$ hr = 2 hr 6 minute

Time = 11 am + 2 hr 6 min = 1:06 pm

Therefore, Work finish at 1:06 PM.