Question

georgia is jogging with a velocity of 4 m/s when she accelerates at 2m/s SQUARE for 3 sec.how fast is geeorgia running now

Answer 1

ANSWER:

Given:

• $u = 4 \ m/s$
• $a = 2 \ m/s^2$
• $t = 3 \ s$
• $v = ?\; \; (to \ be \ found)$

Solution:

$\boxed{\bf{a = \dfrac{v-u}{t}}}$

$\therefore 2 = \dfrac{v - 4}{3}$

$\implies v - 4 = 3 \times 2$

$\implies v - 4 = 6$

$\implies v = 6 + 4$

$\boxed{\implies{\boxed{v = 10 \ m/s}}}$

Answer 2

$\huge\tt{Answer:-}$

$\bf{Given:-}$

• Initial Velocity of Georgia $(u)$ = $4 \ m \ {s}^{-1}$.
• Acceleration $(a)$ = $2 \ m \ {s}^{-2}$.
• Time taken $(t)$ = $3 \ s$.

$\bf{To \ Find:-}$

Final velocity $(v)$ in this case.

____________...

We know,

We know, Acceleration = (Final Velocity - Initial Velocity)/(Time taken)

Or,

$\boxed{a = \frac{v-u}{t}}$

where,

• a = Acceleration
• v = Final Velocity
• u = Initial Velocity
• t = Time Taken

Putting the values:-

${2 \ m \ {s}^{-2} = \frac{v-(4 \ m \ {s}^{-1})}{3 \ s}}$

$\implies \frac{v-(4 \ m \ {s}^{-1})}{3 \ s} = {2 \ m \ {s}^{-2} }$

$\implies v - 4 \ m \ {s}^{-1} = 2 \ m \ {s}^{-2} \cdot 3 \ s$

$\implies v = 6 \ m \ {s}^{-1} + 4 \ m \ {s}^{-1}$

$\boxed{\implies v = 10 \ m \ {s}^{-1}}$ $...(Ans.)$