getting at least one head two coins are thrown
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S = {(H,H) , (H,T) , (T,H) , (T,T)}
n(S) = 4
Atleast One :
Min Heads - 1
Max Heads - 2 (As 2 coins exists)
E= {(H,T) , (T,H) , (H,H) }
n(E) = 3
P(E) = favourable outcomes / total Outcomes
P(E) = n(E)/n(S)
= 3/4
n(S) = 4
Atleast One :
Min Heads - 1
Max Heads - 2 (As 2 coins exists)
E= {(H,T) , (T,H) , (H,H) }
n(E) = 3
P(E) = favourable outcomes / total Outcomes
P(E) = n(E)/n(S)
= 3/4
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