Question

give 2 examples related to pythagoras theorem​

Answer 1

(っ◔◡◔)っ ♥ Hyy Dude ♥

(っ◔◡◔)っ ♥ Find the value of x.

The side opposite the right angle is the side labelled x. ...

...x=√100=10.

Maybe you remember that in an equation like this, x could also be –10, since –10 squared is also 100. ...

Y=√80=√16×5=4√5.

x=√17.45≈4.18 miles. ♥

❤️ hope it's helps you ❤️

Answer 2

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❤️ Answer ❤️

Example 1

Find the value of x.

Find the value of x.triangle with unknown hypotenuse

Find the value of x.triangle with unknown hypotenuseSolution

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:62+82=x2

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:62+82=x2Which is the same as:

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:62+82=x2Which is the same as:100=x2

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:62+82=x2Which is the same as:100=x2Therefore, we can write:

Find the value of x.triangle with unknown hypotenuseSolutionThe side opposite the right angle is the side labelled x. This is the hypotenuse. When applying the Pythagorean theorem, this squared is equal to the sum of the other two sides squared. Mathematically, this means:62+82=x2Which is the same as:100=x2Therefore, we can write:x=100−−−√=10

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Example 2

Find the value of y.

Find the value of y.example where a leg length is unknown

Find the value of y.example where a leg length is unknownSolution

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:64+y2=144

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:64+y2=144Subtracting 64 from both sides:

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:64+y2=144Subtracting 64 from both sides:y2=80

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:64+y2=144Subtracting 64 from both sides:y2=80Therefore:

Find the value of y.example where a leg length is unknownSolutionThe side opposite the right angle has a length of 12. Therefore, we will write:82+y2=122This is the same as:64+y2=144Subtracting 64 from both sides:y2=80Therefore:y=80−−√=16×5−−−−−=4√5

Hope it helps..!!✌️