Question

give 5 pairs of prime numbers whose difference is 4​

Answer 1

Answer:

$\green { (3,7),(7,11),(19,23),(37,41)\:and \:(71,73)}$

$\green {are \: 5\:pairs \:of \:prime \: numbers}$

$\green {whose \: difference \:is \: \red{4}}$

Step-by-step explanation:

Prime numbers :

The numbers which have only two factors i.e 1 and itself is called prime factors.

$\green { (3,7),(7,11),(19,23),(37,41)\:and \:(71,73)}$

$\green {are \: 5\:pairs \:of \:prime \: numbers}$

$\green {whose \: difference \:is \: \red{4}}$

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Answer 2

Answer:

required 5 pairs of prime numbers are (3,7)(7,11)(19,23)(37,4) whose difference is equal to 4