give a example of binary operation solution . inmaths
Answers
Step-by-step explanation:
•Let us show that addition is a binary operation on real numbers (R) and natural numbers (N). So if we add two operands which are natural numbers a and b, the result will also be a natural number. The same holds good for real numbers. Hence,
+ : R x R → R is given by (a, b) → a + b
+ : N x N → N is given by (a, b) → a + b
•Let us show that multiplication is a binary operation on real numbers (R) and natural numbers (N). So if we multiply two operands which are natural numbers a and b, the result will also be a natural number. The same holds good for real numbers. Hence,
x: R x R → R is given by (a, b) → a x b
x: N x N → N is given by (a, b) → a x b
•Let us show that subtraction is a binary operation on real numbers (R). So if we subtract two operands which are real numbers a and b, the result will also be a real number. The same does not hold good for natural numbers. It is because if we take two natural numbers, 3 and 4 as a and b, then 3 – 4 = -1, which is not a natural number. Hence,
– : R x R → R is given by (a, b)→ a – b
Similarly, the division cannot be defined on real numbers. This is because / : R x R → R is given by (a, b)→ aa/b. Now if we take b as 0 here, a/b is not defined.