Question

Give Δ ABC~ΔPQR if AB/PQ=1/3 then find arΔABC/arΔPQR

Answer 1

The ratio of the similar triangles is equal to the square of the ratio of its corresponding sides.

This is the main concept applied.

Answer 2

$triangle \: \: abc \: \: similar \: \: to \: \: triangle \: pqr \\ \frac{ab}{pq} = \frac{1}{3} \\ \frac{ar(triangle \: \: \: abc)}{ar(triangle \: \: \: \: pqr)} = \frac{ {ab}^{2} }{ {pq}^{2} } .....reason \: ..(by \: theroem \: area \: of \: similar \: triangle) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ {1}^{2} }{ {3}^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{9} \\ mark \: as \: brainliest$