Question

Give an account of various corrections in Bomb Calorimeter to get more accurate 

results of calorific value. A sample of coal containing 89% C; 8% H; 3% ash. When this 

coal was tested in laboratory for its calorific value in the bom calorimeter, the following 

data were obtained: Weight of coal burnt: = 0.85 gm; weight of water taken = 650 gm; 

water equivalent of bomb and calorimeter = 2500 gm; Rise in temperature = 2.5 0C; 

Cooling correction = 0.3 0C; Fuse wire correction = 10 Cal; Acid correction = 50 Cal; 

Assuming that latent heat of condensation of steam as 580 cal/gm, calculate the gross and 

net calorific values of the coal in cal/gm.​

Answer 1

Answer:

fogosviz oxbd nd d dj O

Explanation:

bn kbxih uchit uchch disgusts

Answer 2

$GCV = \frac{(W+w)(t2-t1+Cc)-(Ca+Cf+Cct)}{m}$ cal/gm

where GCV=gross calorific value

W = mass of water in calorimeter = 650 gm

w = water equivalent of calorimeter = 2500gm

t1 = initial temperature of water

t2 = final temperature of water

t2-t1 = rise in temperature = 2.5°C

Cc = Cooling correction = 0.3°C

Ca = Acid Correction = 50 cal

Cf = Fuse wire correction = 10 cal

Cct = Cotton thread correction = 0

substituting the values we get

GCV = $\frac{(3150)(2.8)-60}{0.85}$

⇒ GCV = 10305.88 cal/gm

We know Net calorific value NCV = (HCV - 0.09*H*587) cal/gm

Where H= %H in coal

⇒NCV = 10305.88 - 422.64

⇒NCV = 9883.02 cal/gm