give an example of a relation which is not function????? please give. answer
Answers
Answered by
27
before giving example I am describing here what is relation and functions ;-
relation = A relation R from a non - empty set A to a non empty set B is a subset of the Cartesian product A×B .
the subset is is derived by describing a relationship between the first element and the second element of the ordered pairs in A ×B .
well , the second element is called the image of the first element .
let , us take an example of relation ,
consider two sets P = {a,b,c} and Q = {Ali,Bhanu,Binoy,Chandra,Diya}.
than , relation
R={ ( a,Ali),(b,bhanu),(b,binoy),(c,Chandra)}
now , move towards ,
function = A relation f from a set A to a set Bid said to be a function if elements of set A has one and only one image in set B .
or ,
in other words , a function f is a relation from anon empty set A to a non empty set B such that the domain of f is A and no two distinct ordered pairs in f have the same first element.
if f is a function from A to B and (a,b) belongs to f , then f(a) = b , where b is called the image of a under f and a is called the preimage of b under f .
the function f from A to B is denoted by f: A→B.
now , let move toward your question ,,
question :- give an example of relation which is not a function ?
answer ;-
example :- let A = {1,2,3,4,5,6}. define a relation from A to A by R = { (x,y) : y = x+1}
I) write the domain , codomain and range of R .
solution :- we can see that the domain = ( 1,2,3,4,5) .
similarly range = {2,3,4,5,6}
and , the co domain = { 1, 2,3,4,5,6 }.
lokking at the above example we can easily see that the relation in above example is not a function because the element 6 has no image .
_______________________
hope it helps !!
for more query comment in comment box
relation = A relation R from a non - empty set A to a non empty set B is a subset of the Cartesian product A×B .
the subset is is derived by describing a relationship between the first element and the second element of the ordered pairs in A ×B .
well , the second element is called the image of the first element .
let , us take an example of relation ,
consider two sets P = {a,b,c} and Q = {Ali,Bhanu,Binoy,Chandra,Diya}.
than , relation
R={ ( a,Ali),(b,bhanu),(b,binoy),(c,Chandra)}
now , move towards ,
function = A relation f from a set A to a set Bid said to be a function if elements of set A has one and only one image in set B .
or ,
in other words , a function f is a relation from anon empty set A to a non empty set B such that the domain of f is A and no two distinct ordered pairs in f have the same first element.
if f is a function from A to B and (a,b) belongs to f , then f(a) = b , where b is called the image of a under f and a is called the preimage of b under f .
the function f from A to B is denoted by f: A→B.
now , let move toward your question ,,
question :- give an example of relation which is not a function ?
answer ;-
example :- let A = {1,2,3,4,5,6}. define a relation from A to A by R = { (x,y) : y = x+1}
I) write the domain , codomain and range of R .
solution :- we can see that the domain = ( 1,2,3,4,5) .
similarly range = {2,3,4,5,6}
and , the co domain = { 1, 2,3,4,5,6 }.
lokking at the above example we can easily see that the relation in above example is not a function because the element 6 has no image .
_______________________
hope it helps !!
for more query comment in comment box
MOSFET01:
confused now☺️
y r u confused
is this a question of set
yup ,, this is from set
☺️ My weak point ( ... )
No one taught me it clearly
oo,,
if any doubts than , say , ?
Answered by
1
Answer:
one many relations
Step-by-step explanation:
- when all domain are not a relation of range then the relation is not a function
- when the is relation is one-many relation then the relation is not a function
I WILL BE GIVE AN EXAMPLE IN MY COPY
I WILL BE SEND IT.
MARK ME AS BRILLIANT
Attachments:
Similar questions