Question

Give ans as early as possible

Answer 1

let take teta as #

tan # = opposite÷adjacent

sin# = opp÷hyp

cos# = adj÷opp

for tan# = 20/21 compare the above

so , opp = 20 , adj = 21

hyp^2 = opp^2+adj^2

= 400+441

hyp^2 = 841

hyp = 29

now apply the values

sin# = 20/29

cos# = 21/29

Answer 2

$\tan(a ) = \frac{20}{21}$

${ \sec}^{2}(a) = 1 + { \tan }^{2}(a)$

$\sec(a) = \sqrt{ { \tan }^{2}(a) + 1 }$

$\sec(a ) = \sqrt{ \frac{441 + 400}{441} } = \frac{ 29 }{21}$

$\cos(a) = \frac{1}{ \sec(a) } = \frac{21}{ 29 }$

$\sin(a) = \sqrt{1 - \frac{441}{841} } = \sqrt{ \frac{400}{841} } = \frac{20}{29}$

$\cosec(a) = \frac{1}{ \sin(a) } = \frac{29}{20}$

${ \sin }^{2}(a) = 1 - { \cos }^{2}(a)$

$\sin(a) = \sqrt{1 - { \cos }^{2}(a) }$

$\cot(a) = \frac{1}{ \tan(a) } = \frac{21}{20}$