Question

give ans of 7 question ❤​

Answer 1

Answer:

Therefore ∠1>∠3 and BC>DC as size opposite to greater angle are also greater in length. Hence it is proved that either side of triangle is always greater than difference of remaining two sides

Step-by-step explanation:

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Answer 2

Given: XYZ is a triangle.

To Prove: (XY + XZ) > YZ, (YZ + XZ) > XY and (XY + YZ) > XZ

Construction: Produce YX to P such that XP = XZ. Join P and Z.

Statement

1. ∠XZP = ∠XPZ.

2. ∠YZP > ∠XZP.

3. Therefore, ∠YZP > ∠XPZ.

4. ∠YZP > ∠YPZ.

5. In ∆YZP, YP > YZ.

6. (YX + XP) > YZ.

7. (YX + XZ) > YZ. (Proved)

Reason

1. XP = XZ.

2. ∠YZP = ∠YZX + ∠XZP.

3. From 1 and 2.

4. From 3.

5. Greater angle has greater side opposite to it.

6. YP = YX + XP

7. XP = XZ

Similarly, it can be shown that (YZ + XZ) >XY and (XY + YZ) > XZ.