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When only key K1 is closed, then circuit will consist of Lamp L and Resistnce 5 ohm and V = 6v. Current = 0.6A.
Total resistance is circuit = 5 + L
By ohms law,
V=IR
6 = 0.6 ( 5+L)
5+L = 10
L = 5.
So, resistance of Lamp L is 5 ohm.
For rest answer, I have connected an attachment.
Hope it helps :)
Please mark Brainliest ....
Total resistance is circuit = 5 + L
By ohms law,
V=IR
6 = 0.6 ( 5+L)
5+L = 10
L = 5.
So, resistance of Lamp L is 5 ohm.
For rest answer, I have connected an attachment.
Hope it helps :)
Please mark Brainliest ....
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