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iii) (2x + 5)³
Since, (x + y)³ = x³ + 3x²y + 3xy² + y³
Here, x = 2x, y = 5
By substituting the values :
= (2x)³ + 3(2x)²(5) + 3(2x)(5)² + (5)³
= 8x³ + 15(4x²) + 6x(25) + 125
= 8x³ + 60x² + 150x + 125
iv) x³ - 5³
Since x³ - y³ = (x - y)(x² + xy + y²)
Here, x = x, y = 5
By substituting the values :
= (x - 5){(x)² + x(5) + (5)²}
= (x - 5)(x² + 5x + 25)
= x(x² + 5x + 25) - 5(x² + 5x + 25)
= x³ + 5x² + 25x - 5x² - 25x - 125
= x³ - 125
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