give answer of my question
Attachments:
Answers
Answered by
0
I don't know please say the answer.........
Answered by
0
a = 4 - 1/n
d = T2 - T1
= 4 - 2/n - [ 4 - 1/n]
= 4 - 2/n - 4 + 1/n
= - 1/n
Sn = n/2 [ 2a +(n-1) d]
= n/2 [ 8 - 2/n + (n - 1)( - 1/n)
= n/2 [8 - 2/n + ( n) (-1/n) + (-1)(-1/n)]
= n/2[ 8 - 2/n - 1 + 1/n]
= n/2 [ 7 - 1/n]
= 7n/2 - 1/2
= (7n - 1)/2
d = T2 - T1
= 4 - 2/n - [ 4 - 1/n]
= 4 - 2/n - 4 + 1/n
= - 1/n
Sn = n/2 [ 2a +(n-1) d]
= n/2 [ 8 - 2/n + (n - 1)( - 1/n)
= n/2 [8 - 2/n + ( n) (-1/n) + (-1)(-1/n)]
= n/2[ 8 - 2/n - 1 + 1/n]
= n/2 [ 7 - 1/n]
= 7n/2 - 1/2
= (7n - 1)/2
lokesh122344:
galat hai bhai aapka answer
sum ka formula galat hai
Sn=n/2[2a+(n-1)d]. ye hai Sum ka formula
Haa bhai
Pehle maine Tn find kiya tha
thank you bye
Sorry bhai
Similar questions