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Answer 1

♣ Qᴜᴇꜱᴛɪᴏɴ :

• If y = eˣ then  $\sf{\displaystyle\dfrac{d^2y}{dx^2}}$ =

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♣ ᴀɴꜱᴡᴇʀ :

$\sf{\displaystyle\dfrac{d^2y}{dx^2}=e^x}$

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♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

$\sf{\dfrac{d^2y}{dx^2}}$

$\sf{=\dfrac{d^2}{dx^2}\left(e^x\right)}$

$\begin{array}{l}\sf{\dfrac{d}{d x}\left(e^{x}\right)=e^{x} }\\\\\sf{=\dfrac{d}{d x}\left(e^{x}\right) }\\\\\sf{\dfrac{d}{d x}\left(e^{x}\right)=e^{x}}} \\\\\sf{=e^{x}}\end{array}$

Answer 2

Answer:

d is the correct answer hope it helpfull

Step-by-step explanation:

in the past one who not a part of the society as cultural City dweller therefore might have recorded a forest Jeweller as a foreigner