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Step-by-step explanation: join OQ and OR as they are radius of circle they are equal.
as tangents from an external point are equal
So AP=AS(tangent from A). .......1
DS=DR(tangent from D). .......2
AP=AS=5cm.......3
AD=23cm
AD=AS+SD
23=AS+SD
23=5+SD ........from 3
23-5=SD
18cm=SD
DS= DR=18cm.......from 2
CD=29cm
CD=DR+RC
29-18=CR
CR =11cm........4
As angle Cis 90° and OQ=OR
Therefore OQCR is a square.
So OQ=CQ=CR=OR=11cm
Therefore radius of circle is 11cm
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