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Answer:
D) ∠x=55°, ∠y=110°
Step-by-step explaination:
given:
ABCD is a rectangle
solution:
as DC//AB
therefore ∠OCD=∠OAB (alternate interior angles)
as ODC is a isosceles Δ so ∠D=∠C=35°
and ∠D+∠C+∠y=180 (angle sum property)
so ∠y= 180-70= 110°
for ∠x:
on lineDOB ∠y+∠BOC= 180° (leniar pair)
so ∠BOC=70°
using property of an isosceles Δ in ΔBOC
2∠x+∠BOC=180° (angle sum property of Δ)
∠x=55°
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