tan a + tan 2a + tan a tan 2a=1
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Answer:
Tan(3a) = tan(2a+a) [as 3a =2a+a]
Applying the formula,
Tan(A+B)= tanA+tanB/1-tanAtanB
We get ,
Tan(3a)=Tan2a+Tan a / 1-Tan2aTan a
=>tan3a( 1-Tan2aTana) =Tan 2a + Tan a [ cross multiplication]
We get ,
Tan3a- Tan 3aTan2aTan a = Tan2a+ Tana
Now ,
Tan3a-Tan2a-Tan a = Tan 3a Tan2aTan a.
Is the required answer.
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